9x^2-9x+2=0*

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Solution for 9x^2-9x+2=0* equation:



9x^2-9x+2=0*
We move all terms to the left:
9x^2-9x+2-(0*)=0
We add all the numbers together, and all the variables
9x^2-9x+2-0=0
We add all the numbers together, and all the variables
9x^2-9x+2=0
a = 9; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·9·2
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3}{2*9}=\frac{6}{18} =1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3}{2*9}=\frac{12}{18} =2/3 $

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